What happens when you see someone extremely extroverted?

You feel you are good. But the extroverted is damn good.

You are n!. The extroverted is (n!)^n.

If you're a hard working type of individual, you begin to think your combination and hardwork due to conscience by his extrovertedness is same.

i.e. n! × (2^(n(n+1)/2))/((n!)^n)

or (2^(n(n+1)/2))/((n!)^(n-1)) is a function of pi.

In fact it's approximately 5pi by 2.

If we put n as 1.000066 then accuracy improves.

In (2^(n(n+1)/2))/((n!)^(n-1)) if we make a series of 1 in the fashion so as to result something like 1.000066 and so on; then we may get 5pi by 2 accurately.

Possibly that is the crux of Ramanujan-Sato series. One brilliant series over another brilliant series or explanation.

This finishes #PythaShastri endeavours in numbers.

You feel you are good. But the extroverted is damn good.

You are n!. The extroverted is (n!)^n.

If you're a hard working type of individual, you begin to think your combination and hardwork due to conscience by his extrovertedness is same.

i.e. n! × (2^(n(n+1)/2))/((n!)^n)

or (2^(n(n+1)/2))/((n!)^(n-1)) is a function of pi.

In fact it's approximately 5pi by 2.

If we put n as 1.000066 then accuracy improves.

In (2^(n(n+1)/2))/((n!)^(n-1)) if we make a series of 1 in the fashion so as to result something like 1.000066 and so on; then we may get 5pi by 2 accurately.

Possibly that is the crux of Ramanujan-Sato series. One brilliant series over another brilliant series or explanation.

This finishes #PythaShastri endeavours in numbers.

I utilised the hard work done by Ramanujan sir and used his values in the expression above. Here is the screenshot.

1103 is multiplied by 2 and root 2. Then if divided by 99 twice gives 0.318. 1 by pi is 0.318.

( What's the secret? 1/2 can be expressed as a series of 1/3 and 1/9 and 1/27 and so on. The constant e is also a similar series. e series at Heegner numbers gives near about integer. These 3 above mentioned factors help us. Knowledge of early last century is applied)